JEE Math Practice Question
If $$\int {{{\cos x - \sin x} \over {\sqrt {8 - \sin 2x} }}} dx = a{\sin ^{ - 1}}\left( {{{\sin x + \cos x} \over b}} \right) + c$$, where c is a constant of integration, then the ordered pair (a, b) is equal to :
- A.(-1, 3)
- B.(1, 3)
- C.(1, -3)
- D.(3, 1)
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