JEE Math Practice Question

The integral $$\int {{{dx} \over {{{(x + 4)}^{{8 \over 7}}}{{(x - 3)}^{{6 \over 7}}}}}} $$ is equal to : (where C is a constant of integration)

1. A.$${1 \over 2}{\left( {{{x - 3} \over {x + 4}}} \right)^{{3 \over 7}}} + C$$
2. B.$${\left( {{{x - 3} \over {x + 4}}} \right)^{{1 \over 7}}} + C$$
3. C.$$ - {1 \over {13}}{\left( {{{x - 3} \over {x + 4}}} \right)^{{{13} \over 7}}} + C$$
4. D.-$${\left( {{{x - 3} \over {x + 4}}} \right)^{-{1 \over 7}}} + C$$