JEE Math Practice Question
The integral $$\int \, $$cos(loge x) dx is equal to : (where C is a constant of integration)
- A.$${x \over 2}$$[sin(loge x) $$-$$ cos(loge x)] + C
- B.x[cos(loge x) + sin(loge x)] + C
- C.$${x \over 2}$$[cos(loge x) + sin(loge x)] + C
- D.x[cos(loge x) $$-$$ sin(loge x)] + C
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