JEE Math Practice Question
If $$\int {{{dx} \over {{x^3}{{(1 + {x^6})}^{2/3}}}} = xf(x){{(1 + {x^6})}^{{1 \over 3}}} + C} $$ where C is a constant of integration, then the function ƒ(x) is equal to
- A.$${3 \over {{x^2}}}$$
- B.$$ - {1 \over {6{x^3}}}$$
- C.$$ - {1 \over {2{x^3}}}$$
- D.$$ - {1 \over {2{x^2}}}$$
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