JEE Math Practice Question
Let $$a \in \left( {0,{\pi \over 2}} \right)$$ be fixed. If the integral $$\int {{{\tan x + \tan \alpha } \over {\tan x - \tan \alpha }}} dx$$ = A(x) cos 2$$\alpha $$ + B(x) sin 2$$\alpha $$ + C, where C is a constant of integration, then the functions A(x) and B(x) are respectively :
- A.$$x - \alpha $$ and $${\log _e}\left| {\cos \left( {x - \alpha } \right)} \right|$$
- B.$$x + \alpha $$ and $${\log _e}\left| {\sin \left( {x - \alpha } \right)} \right|$$
- C.$$x + \alpha $$ and $${\log _e}\left| {\sin \left( {x + \alpha } \right)} \right|$$
- D.$$x - \alpha $$ and $${\log _e}\left| {\sin \left( {x - \alpha } \right)} \right|$$
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