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JEE Math Practice Question

If $$f\left( {{{x - 4} \over {x + 2}}} \right) = 2x + 1,$$ (x $$ \in $$ R $$-$${1, $$-$$ 2}), then $$\int f \left( x \right)dx$$ is equal to : (where C is a constant of integration)

  1. A.12 loge | 1 $$-$$ x | + 3x + C
  2. B.$$-$$ 12 loge | 1 $$-$$ x | $$-$$ 3x + C
  3. C.12 loge | 1 $$-$$ x | $$-$$ 3x + C
  4. D.$$-$$ 12 loge | 1 $$-$$ x | + 3x + C

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