JEE Math Practice Question
If $$\int {{{2x + 5} \over {\sqrt {7 - 6x - {x^2}} }}} \,\,dx = A\sqrt {7 - 6x - {x^2}} + B{\sin ^{ - 1}}\left( {{{x + 3} \over 4}} \right) + C$$ (where C is a constant of integration), then the ordered pair (A, B) is equal to :
- A.(2, 1)
- B.($$-$$ 2, $$-$$1)
- C.($$-$$ 2, 1)
- D.(2, $$-$$1)
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