JEE Math Practice Question
If $$\,\,\,$$ f$$\left( {{{3x - 4} \over {3x + 4}}} \right)$$ = x + 2, x $$ \ne $$ $$-$$ $${4 \over 3}$$, and $$\int {} $$f(x) dx = A log$$\left| {} \right.$$1 $$-$$ x $$\left| {} \right.$$ + Bx + C, then the ordered pair (A, B) is equal to : (where C is a constant of integration)
- A.$$\left( {{8 \over 3},{2 \over 3}} \right)$$
- B.$$\left( { - {8 \over 3},{2 \over 3}} \right)$$
- C.$$\left( { - {8 \over 3}, - {2 \over 3}} \right)$$
- D.$$\left( { {8 \over 3}, - {2 \over 3}} \right)$$
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