JEE Math Practice Question
The integral $$\int {{{dx} \over {\left( {1 + \sqrt x } \right)\sqrt {x - {x^2}} }}} $$ is equal to : (where C is a constant of integration.)
- A.$$ - 2\sqrt {{{1 + \sqrt x } \over {1 - \sqrt x }}} + C$$
- B.$$ - 2\sqrt {{{1 - \sqrt x } \over {1 + \sqrt x }}} + C$$
- C.$$ - \sqrt {{{1 - \sqrt x } \over {1 + \sqrt x }}} + C$$
- D.$$2\sqrt {{{1 + \sqrt x } \over {1 - \sqrt x }}} + C$$
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