JEE Math Practice Question
Let $m$ and $n$ be the coefficients of seventh and thirteenth terms respectively in the expansion of $\left(\frac{1}{3} x^{\frac{1}{3}}+\frac{1}{2 x^{\frac{2}{3}}}\right)^{18}$. Then $\left(\frac{\mathrm{n}}{\mathrm{m}}\right)^{\frac{1}{3}}$ is :
- A.$\frac{1}{9}$
- B.$\frac{1}{4}$
- C.$\frac{4}{9}$
- D.$\frac{9}{4}$
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