JEE Math Practice Question
Let $\left(a+b x+c x^{2}\right)^{10}=\sum\limits_{i=0}^{20} p_{i} x^{i}, a, b, c \in \mathbb{N}$. If $p_{1}=20$ and $p_{2}=210$, then $2(a+b+c)$ is equal to :
- A.15
- B.8
- C.6
- D.12
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