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JEE Math Practice Question

$$\sum\limits_{\begin{matrix} {i,j = 0} \\ {i \ne j} \\ \end{matrix} }^n {{}^n{C_i}\,{}^n{C_j}} $$ is equal to

  1. A.$$2^{2 n}-{ }^{2 n} C_{n}$$
  2. B.$${2^{2n - 1}} - {}^{2n - 1}{C_{n - 1}}$$
  3. C.$$2^{2 n}-\frac{1}{2}{ }^{2 n} C_{n}$$
  4. D.$${2^{2n - 1}} + {}^{2n - 1}{C_n}$$

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