JEE Math Practice Question
$$\sum\limits_{k = 0}^{20} {{{\left( {{}^{20}{C_k}} \right)}^2}} $$ is equal to :
- A.$${}^{40}{C_{21}}$$
- B.$${}^{40}{C_{19}}$$
- C.$${}^{40}{C_{20}}$$
- D.$${}^{41}{C_{20}}$$
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