JEE Math Practice Question
Let Sn = 1 + q + q2 + . . . . . + qn and Tn = 1 + $$\left( {{{q + 1} \over 2}} \right) + {\left( {{{q + 1} \over 2}} \right)^2}$$ + . . . . . .+ $${\left( {{{q + 1} \over 2}} \right)^n}$$ where q is a real number and q $$ \ne $$ 1. If 101C1 + 101C2 . S1 + .... + 101C101 . S100 = $$\alpha $$T100 then $$\alpha $$ is equal to
- A.202
- B.200
- C.2100
- D.299
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