JEE Math Practice Question
If the third term in the binomial expansion of $${\left( {1 + {x^{{{\log }_2}x}}} \right)^5}$$ equals 2560, then a possible value of x is -
- A.$$2\sqrt 2 $$
- B.$$4\sqrt 2 $$
- C.$${1 \over 8}$$
- D.$${1 \over 4}$$
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