JEE Math Practice Question
The term independent of x in the expansion of $$\left( {{1 \over {60}} - {{{x^8}} \over {81}}} \right).{\left( {2{x^2} - {3 \over {{x^2}}}} \right)^6}$$ is equal to :
- A.36
- B.- 108
- C.- 36
- D.- 72
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