JEE Math Practice Question

If $$x$$ is so small that $${x^3}$$ and higher powers of $$x$$ may be neglected, then $${{{{\left( {1 + x} \right)}^{{3 \over 2}}} - {{\left( {1 + {1 \over 2}x} \right)}^3}} \over {{{\left( {1 - x} \right)}^{{1 \over 2}}}}}$$ may be approximated as

1. A.$$1 - {3 \over 8}{x^2}$$
2. B.$$3x + {3 \over 8}{x^2}$$
3. C.$$ - {3 \over 8}{x^2}$$
4. D.$${x \over 2} - {3 \over 8}{x^2}$$