JEE Math Practice Question

The angle of elevation of the top P of a vertical tower PQ of height 10 from a point A on the horizontal ground is $$45^{\circ}$$. Let R be a point on AQ and from a point B, vertically above $$\mathrm{R}$$, the angle of elevation of $$\mathrm{P}$$ is $$60^{\circ}$$. If $$\angle \mathrm{BAQ}=30^{\circ}, \mathrm{AB}=\mathrm{d}$$ and the area of the trapezium $$\mathrm{PQRB}$$ is $$\alpha$$, then the ordered pair $$(\mathrm{d}, \alpha)$$ is :

1. A.$$(10(\sqrt{3}-1), 25)$$
2. B.$$\left(10(\sqrt{3}-1), \frac{25}{2}\right)$$
3. C.$$(10(\sqrt{3}+1), 25)$$
4. D.$$\left(10(\sqrt{3}+1), \frac{25}{2}\right)$$