JEE Math Practice Question

Let AB and PQ be two vertical poles, 160 m apart from each other. Let C be the middle point of B and Q, which are feet of these two poles. Let $${\pi \over 8}$$ and $$\theta$$ be the angles of elevation from C to P and A, respectively. If the height of pole PQ is twice the height of pole AB, then tan2$$\theta$$ is equal to

1. A.$${{3 - 2\sqrt 2 } \over 2}$$
2. B.$${{3 + \sqrt 2 } \over 2}$$
3. C.$${{3 - 2\sqrt 2 } \over 4}$$
4. D.$${{3 - \sqrt 2 } \over 4}$$