JEE Math Practice Question
A pole stands vertically inside a triangular park ABC. Let the angle of elevation of the top of the pole from each corner of the park be $${\pi \over 3}$$. If the radius of the circumcircle of $$\Delta$$ABC is 2, then the height of the pole is equal to :
- A.$${{1 \over {\sqrt 3 }}}$$
- B.2$${\sqrt 3 }$$
- C.$${\sqrt 3 }$$
- D.$${{{2\sqrt 3 } \over 3}}$$
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