JEE Math Practice Question
A man on the top of a vertical tower observes a car moving at a uniform speed towards the tower on a horizontal road. If it takes 18 min. for the angle of depression of the car to change from 30o to 45o ; then after this, the time taken (in min.) by the car to reach the foot of the tower, is :
- A.$$9\left( {1 + \sqrt 3 } \right)$$
- B.$$18\left( {1 + \sqrt 3 } \right)$$
- C.$$18\left( {\sqrt 3 - 1} \right)$$
- D.$${9 \over 2}\left( {\sqrt 3 - 1} \right)$$
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