JEE Math Practice Question
Let the three sides of a triangle are on the lines $4 x-7 y+10=0, x+y=5$ and $7 x+4 y=15$. Then the distance of its orthocentre from the orthocentre of the tringle formed by the lines $x=0, y=0$ and $x+y=1$ is
- A.$\sqrt{20}$
- B.$20$
- C.$\sqrt{5}$
- D.$5$
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