JEE Math Practice Question
Let $$A(a, b), B(3,4)$$ and $$C(-6,-8)$$ respectively denote the centroid, circumcentre and orthocentre of a triangle. Then, the distance of the point $$P(2 a+3,7 b+5)$$ from the line $$2 x+3 y-4=0$$ measured parallel to the line $$x-2 y-1=0$$ is
- A.$$\frac{17 \sqrt{5}}{6}$$
- B.$$\frac{15 \sqrt{5}}{7}$$
- C.$$\frac{17 \sqrt{5}}{7}$$
- D.$$\frac{\sqrt{5}}{17}$$
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