JEE Math Practice Question
If the point $$\left(\alpha, \frac{7 \sqrt{3}}{3}\right)$$ lies on the curve traced by the mid-points of the line segments of the lines $$x \cos \theta+y \sin \theta=7, \theta \in\left(0, \frac{\pi}{2}\right)$$ between the co-ordinates axes, then $$\alpha$$ is equal to :
- A.$$-$$7
- B.7
- C.$$-$$7$$\sqrt3$$
- D.7$$\sqrt3$$
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