JEE Math Practice Question
Let A be the set of all points ($$\alpha$$, $$\beta$$) such that the area of triangle formed by the points (5, 6), (3, 2) and ($$\alpha$$, $$\beta$$) is 12 square units. Then the least possible length of a line segment joining the origin to a point in A, is :
- A.$${4 \over {\sqrt 5 }}$$
- B.$${16 \over {\sqrt 5 }}$$
- C.$${8 \over {\sqrt 5 }}$$
- D.$${12 \over {\sqrt 5 }}$$
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