JEE Math Practice Question
Let A be a fixed point (0, 6) and B be a moving point (2t, 0). Let M be the mid-point of AB and the perpendicular bisector of AB meets the y-axis at C. The locus of the mid-point P of MC is :
- A.3x2 $$-$$ 2y $$-$$ 6 = 0
- B.3x2 + 2y $$-$$ 6 = 0
- C.2x2 + 3y $$-$$ 9 = 0
- D.2x2 $$-$$ 3y + 9 = 0
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