JEE Math Practice Question
Let the equations of two sides of a triangle be 3x $$-$$ 2y + 6 = 0 and 4x + 5y $$-$$ 20 = 0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is :
- A.122y $$-$$ 26x $$-$$ 1675 = 0
- B.122y + 26x + 1675 = 0
- C.26x + 61y + 1675 = 0
- D.26x $$-$$ 122y $$-$$ 1675 = 0
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