JEE Math Practice Question
The point (2, 1) is translated parallel to the line L : x− y = 4 by $$2\sqrt 3 $$ units. If the newpoint Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is :
- A.x + y = 2 $$-$$ $$\sqrt 6 $$
- B.x + y = 3 $$-$$ 3$$\sqrt 6 $$
- C.x + y = 3 $$-$$ 2$$\sqrt 6 $$
- D.2x + 2y = 1 $$-$$ $$\sqrt 6 $$
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