JEE Math Practice Question
A straight line through origin O meets the lines 3y = 10 − 4x and 8x + 6y + 5 = 0 at points A and B respectively. Then O divides the segment AB in the ratio :
- A.2 : 3
- B.1 : 2
- C.4 : 1
- D.3 : 4
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