JEE Math Practice Question
Let $y=y(x)$ be the solution of the differential equation $\frac{d y}{d x}+3\left(\tan ^2 x\right) y+3 y=\sec ^2 x, y(0)=\frac{1}{3}+e^3$. Then $y\left(\frac{\pi}{4}\right)$ is equal to :
- A.$\frac{4}{3}$
- B.$\frac{2}{3}+e^3$
- C.$\frac{4}{3}+e^3$
- D.$\frac{2}{3}$
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