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JEE Math Practice Question

Let $\mathrm{y}=\mathrm{y}(\mathrm{x})$ be the solution of the differential equation $\left(x y-5 x^2 \sqrt{1+x^2}\right) d x+\left(1+x^2\right) d y=0, y(0)=0$. Then $y(\sqrt{3})$ is equal to

  1. A.$\frac{5 \sqrt{3}}{2}$
  2. B.$\sqrt{\frac{15}{2}}$
  3. C.$\sqrt{\frac{14}{3}}$
  4. D.$2 \sqrt{2}$

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