JEE Math Practice Question
Suppose the solution of the differential equation $$\frac{d y}{d x}=\frac{(2+\alpha) x-\beta y+2}{\beta x-2 \alpha y-(\beta \gamma-4 \alpha)}$$ represents a circle passing through origin. Then the radius of this circle is :
- A.$$\sqrt{17}$$
- B.2
- C.$$\frac{\sqrt{17}}{2}$$
- D.$$\frac{1}{2}$$
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