JEE Math Practice Question
Let $$y=y(x)$$ be the solution of the differential equation $$(1+y^2) e^{\tan x} d x+\cos ^2 x(1+e^{2 \tan x}) d y=0, y(0)=1$$. Then $$y\left(\frac{\pi}{4}\right)$$ is equal to
- A.$$\frac{1}{e^2}$$
- B.$$\frac{2}{e^2}$$
- C.$$\frac{2}{e}$$
- D.$$\frac{1}{e}$$
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