JEE Math Practice Question
The solution of the differential equation $$(x^2+y^2) \mathrm{d} x-5 x y \mathrm{~d} y=0, y(1)=0$$, is :
- A.$$\left|x^2-4 y^2\right|^5=x^2$$
- B.$$\left|x^2-2 y^2\right|^6=x$$
- C.$$\left|x^2-2 y^2\right|^5=x^2$$
- D.$$\left|x^2-4 y^2\right|^6=x$$
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