JEE Math Practice Question
Let $$\int\limits_0^x \sqrt{1-\left(y^{\prime}(t)\right)^2} d t=\int_0^x y(t) d t, 0 \leq x \leq 3, y \geq 0, y(0)=0$$. Then at $$x=2, y^{\prime \prime}+y+1$$ is equal to
- A.$$\sqrt2$$
- B.2
- C.1/2
- D.1
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