JEE Math Practice Question
Let $$y=y(x)$$ be the solution of the differential equation $$\sec x \mathrm{~d} y+\{2(1-x) \tan x+x(2-x)\} \mathrm{d} x=0$$ such that $$y(0)=2$$. Then $$y(2)$$ is equal to:
- A.$$2\{\sin (2)+1\}$$
- B.2
- C.1
- D.$$2\{1-\sin (2)\}$$
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