JEE Math Practice Question
The temperature $$T(t)$$ of a body at time $$t=0$$ is $$160^{\circ} \mathrm{F}$$ and it decreases continuously as per the differential equation $$\frac{d T}{d t}=-K(T-80)$$, where $$K$$ is a positive constant. If $$T(15)=120^{\circ} \mathrm{F}$$, then $$T(45)$$ is equal to
- A.90$$^\circ$$ F
- B.85$$^\circ$$ F
- C.80$$^\circ$$ F
- D.95$$^\circ$$ F
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