JEE Math Practice Question

If $$y=y(x)$$ is the solution curve of the differential equation $$\left(x^2-4\right) \mathrm{d} y-\left(y^2-3 y\right) \mathrm{d} x=0, x>2, y(4)=\frac{3}{2}$$ and the slope of the curve is never zero, then the value of $$y(10)$$ equals :

1. A.$$\frac{3}{1+(8)^{1 / 4}}$$
2. B.$$\frac{3}{1-(8)^{1 / 4}}$$
3. C.$$\frac{3}{1-2 \sqrt{2}}$$
4. D.$$\frac{3}{1+2 \sqrt{2}}$$