JEE Math Practice Question
Let $$y = y(x)$$ be the solution of the differential equation $${x^3}dy + (xy - 1)dx = 0,x > 0,y\left( {{1 \over 2}} \right) = 3 - \mathrm{e}$$. Then y (1) is equal to
- A.2 $$-$$ e
- B.3
- C.1
- D.e
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