JEE Math Practice Question
Let $$y=y(x)$$ be the solution of the differential equation $$(x^2-3y^2)dx+3xy~dy=0,y(1)=1$$. Then $$6y^2(e)$$ is equal to
- A.$$\frac{3}{2}\mathrm{e}^2$$
- B.$$3\mathrm{e}^2$$
- C.$$\mathrm{e}^2$$
- D.$$2\mathrm{e}^2$$
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