JEE Math Practice Question
Let $$y=f(x)$$ be the solution of the differential equation $$y(x+1)dx-x^2dy=0,y(1)=e$$. Then $$\mathop {\lim }\limits_{x \to {0^ + }} f(x)$$ is equal to
- A.$${e^2}$$
- B.0
- C.$${1 \over {{e^2}}}$$
- D.$${1 \over e}$$
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