JEE Math Practice Question
If x = x(y) is the solution of the differential equation $$y{{dx} \over {dy}} = 2x + {y^3}(y + 1){e^y},\,x(1) = 0$$; then x(e) is equal to :
- A.$${e^3}({e^e} - 1)$$
- B.$${e^e}({e^3} - 1)$$
- C.$${e^2}({e^e} + 1)$$
- D.$${e^e}({e^2} - 1)$$
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