JEE Math Practice Question
If $$y = y(x)$$ is the solution of the differential equation $$2{x^2}{{dy} \over {dx}} - 2xy + 3{y^2} = 0$$ such that $$y(e) = {e \over 3}$$, then y(1) is equal to :
- A.$${1 \over 3}$$
- B.$${2 \over 3}$$
- C.$${3 \over 2}$$
- D.3
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