JEE Math Practice Question
Let y = y(x) be the solution of the differential equation $$x(1 - {x^2}){{dy} \over {dx}} + (3{x^2}y - y - 4{x^3}) = 0$$, $$x > 1$$, with $$y(2) = - 2$$. Then y(3) is equal to :
- A.$$-$$18
- B.$$-$$12
- C.$$-$$6
- D.$$-$$3
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