JEE Math Practice Question
Let x = x(y) be the solution of the differential equation $$2y\,{e^{x/{y^2}}}dx + \left( {{y^2} - 4x{e^{x/{y^2}}}} \right)dy = 0$$ such that x(1) = 0. Then, x(e) is equal to :
- A.$$e{\log _e}(2)$$
- B.$$ - e{\log _e}(2)$$
- C.$${e^2}{\log _e}(2)$$
- D.$$ - {e^2}{\log _e}(2)$$
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