JEE Math Practice Question
Let the solution curve of the differential equation $$x{{dy} \over {dx}} - y = \sqrt {{y^2} + 16{x^2}} $$, $$y(1) = 3$$ be $$y = y(x)$$. Then y(2) is equal to:
- A.15
- B.11
- C.13
- D.17
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