%%

JEE Math Practice Question

If y = y(x) is the solution curve of the differential equation $${x^2}dy + \left( {y - {1 \over x}} \right)dx = 0$$ ; x > 0 and y(1) = 1, then $$y\left( {{1 \over 2}} \right)$$ is equal to :

  1. A.$${3 \over 2} - {1 \over {\sqrt e }}$$
  2. B.$$3 + {1 \over {\sqrt e }}$$
  3. C.3 + e
  4. D.3 $$-$$ e

Want to know if you got it right?

Answer this and thousands more real JEE previous-year questions free, get graded instantly, and climb the global ranked leaderboard.

Practice JEE free →

More JEE Math questions