JEE Math Practice Question
If $${{dy} \over {dx}} = {{{2^{x + y}} - {2^x}} \over {{2^y}}}$$, y(0) = 1, then y(1) is equal to :
- A.log2(2 + e)
- B.log2(1 + e)
- C.log2(2e)
- D.log2(1 + e2)
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