JEE Math Practice Question
If the solution curve of the differential equation (2x $$-$$ 10y3)dy + ydx = 0, passes through the points (0, 1) and (2, $$\beta$$), then $$\beta$$ is a root of the equation :
- A.y5 $$-$$ 2y $$-$$ 2 = 0
- B.2y5 $$-$$ 2y $$-$$ 1 = 0
- C.2y5 $$-$$ y2 $$-$$ 2 = 0
- D.y5 $$-$$ y2 $$-$$ 1 = 0
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