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JEE Math Practice Question

Let y = y(x) be the solution of the differential equation $${{dy} \over {dx}} = 2(y + 2\sin x - 5)x - 2\cos x$$ such that y(0) = 7. Then y($$\pi$$) is equal to :

  1. A.$$2{e^{{\pi ^2}}} + 5$$
  2. B.$${e^{{\pi ^2}}} + 5$$
  3. C.$$3{e^{{\pi ^2}}} + 5$$
  4. D.$$7{e^{{\pi ^2}}} + 5$$

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